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数论 MSE 6 票 1 回答 129 浏览 已读

Why am I finding the Catalan numbers in these "Snowball Numbers"?

weissguy
I've been having fun trying to find new number systems that aren't in the OEIS. One such number system, is the "Snowball Numbers", which I will define below. Apologies if these have been explored before, I could not find them. While playing with these numbers, I found the Catalan numbers (?!)...
代数几何 MSE 0 票 0 回答 22 浏览 未读

Compactness of Projective Varieties

Tltxtmath
How can I show that every Projective variety in $\mathbb{P}^n$ is compact in the induced Euclidean topology? Should I consider, as customary, an arbitrary open cover in $\mathbb{P}^n$, and perhaps use the projection map $\pi:\mathbb{C}^{n+1}\setminus\{0\}\rightarrow \mathbb{P}^n$ which defines...
数论 MSE 0 票 1 回答 32 浏览 未读

Is $n=1$ the only solution to $\operatorname{rev}\left(\sum_{i=0}^{p_n} p_{n+1}^i\right) = \sum_{i=0}^{p_n} p_{n+2}^i$?

Rayhan Ahmed
Let $p_k$ denote the $k$-th prime number, and let $\operatorname{rev}(x)$ denote the decimal digit-reversal of a positive integer $x$. Define the consecutive-prime geometric sums: $$A_n = \sum_{i=0}^{p_n} p_{n+1}^i = \frac{p_{n+1}^{p_n + 1} - 1}{p_{n+1} - 1}, \qquad B_n = \sum_{i=0}^{p_n}...
数论 MSE 0 票 0 回答 55 浏览 未读

Has the Josephus sequence $J(n,1),J(n,2),\dots$ been studied from a coverage viewpoint?

gabnash
I have been investigating an empirical variant of the classical Josephus problem and would like to know whether it has been studied previously. Let $J(n,k)$ denote the survivor of the classical Josephus problem with population size $n$ and elimination interval $k$. For fixed $n$, instead of...
代数几何 MSE 0 票 0 回答 42 浏览 未读

Classification/Types of reductive groups

user14411
Let $G$ be a reductive group over a field $k$. What actually does it mean to say that $G$ is of type $A_n, B_n,\dots,G_2,{}^2A_n, {}^3D_4,...$? In case it helps, I know what the Dynkin diagrams of types $A_n, B_n,\dots,G_2$ are (but not those of types ${}^2A_n, {}^3D_4,...$). I also know how to...
代数几何 MSE 0 票 0 回答 38 浏览 未读

The morphism $\phi: k \to V$ given by $\phi(t)= (t^2,t^3) $ is not an isomorphism

HMPQ
This statement is given as application of earlier results on the page $22 $ of the Daniel Perrin's Algebraic Geometry textbook from which I am self studying. Here $k$ is a commutative field and $V$ is a affine algebraic set. Application $6.9$ The morphism $\phi: k \to V=V(Y^2-X^3)$ given by...
解析数论 MSE 3 票 0 回答 39 浏览 未读

Asymptotics for the Dirichlet convolution $a * \varphi = 2a - \epsilon$ and the roots of $2\zeta(s) = \zeta(s-1)$

N. Fischer
Consider the sequence defined by $a_1 = 1$ and the recurrence relation for $n \ge 2$: $$a_n = \sum_{k=1}^{n-1} a_{\gcd(n,k)}$$ Grouping the terms by their divisors $d = \gcd(n,k)$, the number of integers $k < n$ such that $\gcd(n,k) = d$ is given by $\varphi(n/d)$, where $\varphi$ is Euler's...
数论 MSE 1 票 0 回答 25 浏览 未读

Asymptotic growth of the clique number for the &quot;Prime-Visibility Graph&quot; on an $N \times N$ grid

Kinheadpump
Background & Definition In lattice geometry, two points $A, B \in \mathbb{Z}^2$ are said to be visible to one another if the open line segment between them contains no other lattice points. Equivalently, if $A = (x_A, y_A)$ and $B = (x_B, y_B)$, they are visible if $\gcd(|x_A - x_B|, |y_A -...
数论 MSE 3 票 0 回答 52 浏览 未读

Recursive sequence $a_{k+1} = a_k - \gcd(a_k, (n+k)^2 - 1)$ generating twin primes

Kinheadpump
I have been analyzing a recursive sequence based on the greatest common divisor that acts as a dynamic sieve for twin primes. It shares structural similarities with Rowland's prime-generating sequence but targets the difference of squares. For any integer $n \ge 2$, define the sequence...
数论 MSE 3 票 0 回答 64 浏览 未读

Near-misses to the Fermat quintic threefold $x_1^5+x_2^5+x_3^5+x_4^5+x_5^5=0$

Tito Piezas III
The Fermat quintic threefold is given by the equation, $$x_1^5+x_2^5+x_3^5+x_4^5+x_5^5=0\qquad\qquad$$ $\hskip1.5in$ (Incidentally, this threefold is a Calabi-Yau manifold, a type of manifold important to string theory.) In the integers, there are only four primitive solutions known, two which...
模形式 MSE 1 票 0 回答 21 浏览 未读

Waldspurger formula for Fourier coefficients of forms in Kohnen&#39;s space.

user1768527
Let $f\in S_{k+1/2}^+(4q)$ be a newform in Kohnen’s space for $q$ an odd, square-free integer. For simplicity, assume that $k$ is even. Let $$f(z) = \sum_{\substack{n\geq 1\\ n\equiv 0,1\mod 4}}a_f(n)e(nz)$$ denote the Fourier expansion of $f$ at the cusp $\infty$. Let $D>0$ be a fundamental...
模形式 MSE 2 票 0 回答 27 浏览 未读

Clarifying Confusion with Hecke Operators and Double Cosets

Snastt
I am confused about the construction of the Hecke operators. I am defining them on $\Gamma_{1}(N)$ as $$(T_{m}f)(z) = \sum_{\substack{a,d \ge 1 \\ ad = m}}\langle a\rangle\left[\Gamma_{1}(N)\begin{pmatrix} a & 0 \\ 0 & d \end{pmatrix}\Gamma_{1}(N)\right]_{k}f(z),$$ where $\langle a \rangle$ is...
代数几何 MSE 2 票 0 回答 60 浏览 未读

Prove $\mathcal{O}_{X_{\text{&#233;t}}}(U) = \Gamma(U,\mathcal{O}_{U})$ is a sheaf on $X_{\text{&#233;t}}$.

conan
For $U \to X$ étale, define a presheaf by $\mathcal{O}_{X_{\text{ét}}}(U) = \Gamma(U,\mathcal{O}_{U})$. I want to show that this is a sheaf on $X_{\text{ét}}$. Clearly, the sheaf condition holds for all Zariski open coverings, so it is sufficient to show the sheaf condition holds for étale...
代数几何 MSE 1 票 0 回答 61 浏览 未读

$k[X,Y]/(F,G)$ is a finite dimensional $k$-vector space

HMPQ
Let $k$ be an algebraically closed field and $V$ be an affine variety. From Page 19 of Daniel Perrin’s Algebraic geometry. Lemma: Let $F,G\in k [X,Y]$ be non-zero polynomials without common factors, there is a non-zero polynomial $d\in k[X]$ and polynomials $A,B\in k[X,Y]$ such that $d= AF+BG$...
代数几何 MSE 0 票 0 回答 21 浏览 未读

A question in the proof that the map $\gamma: \phi \to \phi^*$ from $Reg(V,W)$ to $Hom_{k-alg }( \Gamma(W), \Gamma(V))$ is bijective

HMPQ
I am self studying Algebraic Geometry from Daniel Perrin's Algebraic Geometry. $k$ is an algebraically closed field. $\Gamma(V)$ is image of $r: k[X_1,...,X_n]\to F(V,k)$ and $V,W$ is affine algebraic set. $\theta : \Gamma(W) \to \Gamma(V)$ be a homomorphism of $k-$algebras and $\phi: V\to k^m$...
代数几何 MSE 0 票 0 回答 22 浏览 未读

Prove that $\Gamma$ is an equivalence of categories between the category of affine algebraic sets and the category of reduced $k-$ algebras

HMPQ
I am self studying Algebraic Geometry from the Daniel Perrin's textbook. $k$ is an algebraically closed field. $\Gamma(V)$ is image of $r: k[X_1,...,X_n]\to F(V,k)$ and $V,W$ is affine algebraic set. $\theta : \Gamma(W) \to \Gamma(V)$ be a homomorphism of $k-$algebras and $\phi: V\to k^m$ is the...
解析数论 MSE 3 票 1 回答 80 浏览 未读

Almost-all Goldbach for the quadratic sequence $9n^2+1$?

Yoyos Tutoring
Let $$B:=\{n\geq 13: n \text{ odd and there exists a prime } q \text{ such that } 9n^2+1-q \text{ is prime, where either } q=3, \text{or } q\geq 11,q \equiv 2\pmod 3, q-1 \text{ is not a square}\}$$ I am trying to understand whether the following “almost-all Goldbach” statement is known /...
数论 MSE 0 票 0 回答 25 浏览 未读

Density of a self-avoiding quadratic sequence with hierarchical &quot;modular&quot; valves

Aurelian Florea
I am exploring a family of integer sequences $(k_n)$ that combine explosive quadratic growth with specific "modular" reduction rules based on the proximity to perfect squares and powers of two. I’ve categorized these reduction mechanisms as "Valves." The Core Growth Function: Let $f(x) = ax^2 +...
数论 MSE 0 票 0 回答 43 浏览 未读

Does anyone know how to solve it via vieta root jumping?

anon
Let $(a,b,c)$ be positive integers such that a $abc+1 \mid a^2+b^2+c^2$. Then $\dfrac{a^2+b^2+c^2}{abc+1}$ can be written as the sum of 2 positive squares. Proposed by Sam Vandervelde.
数论 MSE 0 票 0 回答 8 浏览 未读

The Centrality of Galois Groups of Local and Global Fields of Dimension One

A Caeiro
Professor Manin's 1990 ICM talk states there is a convincing case to be made that these groups are, in some sense, "more fundamental" in number theory than even the integers. The talk's purpose being a broadest-possible survey of the works of Professor Drinfel'd, Professor Manin does not deem it...